2/7x+28=63-3x

Solution for 2/7x+28=63-3x equation:

2/7x+28=63-3x

We move all terms to the left:

2/7x+28-(63-3x)=0


Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R


We add all the numbers together, and all the variables

2/7x-(-3x+63)+28=0

We get rid of parentheses

2/7x+3x-63+28=0

We multiply all the terms by the denominator


3x*7x-63*7x+28*7x+2=0

Wy multiply elements

21x^2-441x+196x+2=0

We add all the numbers together, and all the variables

21x^2-245x+2=0

a = 21; b = -245; c = +2;
Δ = b2-4ac
Δ = -2452-4·21·2
Δ = 59857
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-245)-\sqrt{59857}}{2*21}=\frac{245-\sqrt{59857}}{42}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-245)+\sqrt{59857}}{2*21}=\frac{245+\sqrt{59857}}{42}
$