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2/7x+2=3/5x
We move all terms to the left:
2/7x+2-(3/5x)=0
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/7x-(+3/5x)+2=0
We get rid of parentheses
2/7x-3/5x+2=0
We calculate fractions
10x/35x^2+(-21x)/35x^2+2=0
We multiply all the terms by the denominator
10x+(-21x)+2*35x^2=0
Wy multiply elements
70x^2+10x+(-21x)=0
We get rid of parentheses
70x^2+10x-21x=0
We add all the numbers together, and all the variables
70x^2-11x=0
a = 70; b = -11; c = 0;
Δ = b2-4ac
Δ = -112-4·70·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-11}{2*70}=\frac{0}{140} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+11}{2*70}=\frac{22}{140} =11/70 $
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