2/7x+2=3/8x

Solution for 2/7x+2=3/8x equation:

2/7x+2=3/8x

We move all terms to the left:

2/7x+2-(3/8x)=0


Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



Domain of the equation: 8x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2/7x-(+3/8x)+2=0

We get rid of parentheses

2/7x-3/8x+2=0

We calculate fractions


16x/56x^2+(-21x)/56x^2+2=0

We multiply all the terms by the denominator


16x+(-21x)+2*56x^2=0

Wy multiply elements

112x^2+16x+(-21x)=0

We get rid of parentheses

112x^2+16x-21x=0

We add all the numbers together, and all the variables

112x^2-5x=0

a = 112; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·112·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*112}=\frac{0}{224}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*112}=\frac{10}{224}
=5/112
$