2/7x+3/14=1/8x+6

Solution for 2/7x+3/14=1/8x+6 equation:

2/7x+3/14=1/8x+6

We move all terms to the left:

2/7x+3/14-(1/8x+6)=0


Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



Domain of the equation: 8x+6)!=0

x∈R


We get rid of parentheses

2/7x-1/8x-6+3/14=0

We calculate fractions


1344x^2/784x^2+224x/784x^2+(-98x)/784x^2-6=0

We multiply all the terms by the denominator


1344x^2+224x+(-98x)-6*784x^2=0

Wy multiply elements

1344x^2-4704x^2+224x+(-98x)=0

We get rid of parentheses

1344x^2-4704x^2+224x-98x=0

We add all the numbers together, and all the variables

-3360x^2+126x=0

a = -3360; b = 126; c = 0;
Δ = b2-4ac
Δ = 1262-4·(-3360)·0
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(126)-126}{2*-3360}=\frac{-252}{-6720}
=3/80
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(126)+126}{2*-3360}=\frac{0}{-6720}
=0
$