2/7x+5/14x=18

Solution for 2/7x+5/14x=18 equation:

2/7x+5/14x=18

We move all terms to the left:

2/7x+5/14x-(18)=0


Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



Domain of the equation: 14x!=0

x!=0/14

x!=0

x∈R


We calculate fractions


28x/98x^2+35x/98x^2-18=0

We multiply all the terms by the denominator


28x+35x-18*98x^2=0

We add all the numbers together, and all the variables

63x-18*98x^2=0

Wy multiply elements

-1764x^2+63x=0

a = -1764; b = 63; c = 0;
Δ = b2-4ac
Δ = 632-4·(-1764)·0
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-63}{2*-1764}=\frac{-126}{-3528}
=1/28
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+63}{2*-1764}=\frac{0}{-3528}
=0
$