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2/7x-2/5x=8
We move all terms to the left:
2/7x-2/5x-(8)=0
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
10x/35x^2+(-14x)/35x^2-8=0
We multiply all the terms by the denominator
10x+(-14x)-8*35x^2=0
Wy multiply elements
-280x^2+10x+(-14x)=0
We get rid of parentheses
-280x^2+10x-14x=0
We add all the numbers together, and all the variables
-280x^2-4x=0
a = -280; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·(-280)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*-280}=\frac{0}{-560} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*-280}=\frac{8}{-560} =-1/70 $
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