2/7x-3/8x+1/4=1/7

Solution for 2/7x-3/8x+1/4=1/7 equation:

2/7x-3/8x+1/4=1/7

We move all terms to the left:

2/7x-3/8x+1/4-(1/7)=0


Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R


We add all the numbers together, and all the variables

2/7x-3/8x+1/4-(+1/7)=0

We get rid of parentheses

2/7x-3/8x+1/4-1/7=0

We calculate fractions


3136x^2/6272x^2+256x/6272x^2+(-2352x)/6272x^2+(-128x)/6272x^2=0

We multiply all the terms by the denominator


3136x^2+256x+(-2352x)+(-128x)=0

We get rid of parentheses

3136x^2+256x-2352x-128x=0

We add all the numbers together, and all the variables

3136x^2-2224x=0

a = 3136; b = -2224; c = 0;
Δ = b2-4ac
Δ = -22242-4·3136·0
Δ = 4946176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4946176}=2224$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2224)-2224}{2*3136}=\frac{0}{6272}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2224)+2224}{2*3136}=\frac{4448}{6272}
=139/196
$