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2/7x-5/2=-3/14x+1
We move all terms to the left:
2/7x-5/2-(-3/14x+1)=0
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
Domain of the equation: 14x+1)!=0We get rid of parentheses
x∈R
2/7x+3/14x-1-5/2=0
We calculate fractions
(-490x^2)/392x^2+112x/392x^2+84x/392x^2-1=0
We multiply all the terms by the denominator
(-490x^2)+112x+84x-1*392x^2=0
We add all the numbers together, and all the variables
(-490x^2)+196x-1*392x^2=0
Wy multiply elements
(-490x^2)-392x^2+196x=0
We get rid of parentheses
-490x^2-392x^2+196x=0
We add all the numbers together, and all the variables
-882x^2+196x=0
a = -882; b = 196; c = 0;
Δ = b2-4ac
Δ = 1962-4·(-882)·0
Δ = 38416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{38416}=196$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(196)-196}{2*-882}=\frac{-392}{-1764} =2/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(196)+196}{2*-882}=\frac{0}{-1764} =0 $
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