2/7y+10=-1/2y+6

Solution for 2/7y+10=-1/2y+6 equation:

2/7y+10=-1/2y+6

We move all terms to the left:

2/7y+10-(-1/2y+6)=0


Domain of the equation: 7y!=0

y!=0/7

y!=0

y∈R



Domain of the equation: 2y+6)!=0

y∈R


We get rid of parentheses

2/7y+1/2y-6+10=0

We calculate fractions


4y/14y^2+7y/14y^2-6+10=0

We add all the numbers together, and all the variables

4y/14y^2+7y/14y^2+4=0

We multiply all the terms by the denominator


4y+7y+4*14y^2=0

We add all the numbers together, and all the variables

11y+4*14y^2=0

Wy multiply elements

56y^2+11y=0

a = 56; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·56·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*56}=\frac{-22}{112}
=-11/56
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*56}=\frac{0}{112}
=0
$