2/7y+9=1/2y+7

Solution for 2/7y+9=1/2y+7 equation:

2/7y+9=1/2y+7

We move all terms to the left:

2/7y+9-(1/2y+7)=0


Domain of the equation: 7y!=0

y!=0/7

y!=0

y∈R



Domain of the equation: 2y+7)!=0

y∈R


We get rid of parentheses

2/7y-1/2y-7+9=0

We calculate fractions


4y/14y^2+(-7y)/14y^2-7+9=0

We add all the numbers together, and all the variables

4y/14y^2+(-7y)/14y^2+2=0

We multiply all the terms by the denominator


4y+(-7y)+2*14y^2=0

Wy multiply elements

28y^2+4y+(-7y)=0

We get rid of parentheses

28y^2+4y-7y=0

We add all the numbers together, and all the variables

28y^2-3y=0

a = 28; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·28·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*28}=\frac{0}{56}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*28}=\frac{6}{56}
=3/28
$