2/83;z=16

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Solution for 2/83;z=16 equation: 



2/83z=16

We move all terms to the left:

2/83z-(16)=0



Domain of the equation: 83z!=0

z!=0/83

z!=0

z∈R



We multiply all the terms by the denominator


-16*83z+2=0

Wy multiply elements

-1328z+2=0

We move all terms containing z to the left, all other terms to the right

-1328z=-2

z=-2/-1328

z=1/664

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