2/8=n+4/n-4

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Solution for 2/8=n+4/n-4 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

2/8 = n+4/n-4 // - n+4/n-4

2/8-n-(4/n)+4 = 0

2/8-n-4*n^-1+4 = 0

17/4*n^0-1*n^1-4*n^-1 = 0

(17/4*n^1-1*n^2-4*n^0)/(n^1) = 0 // * n^2

n^1*(17/4*n^1-1*n^2-4*n^0) = 0

n^1

(17/4)*n-n^2-4 = 0

(17/4)*n-n^2-4 = 0

DELTA = (17/4)^2-(-4*(-1)*4)

DELTA = 33/16

DELTA > 0

n = ((33/16)^(1/2)-(17/4))/(-1*2) or n = (-(17/4)-(33/16)^(1/2))/(-1*2)

n = ((33/16)^(1/2)-17/4)/(-2) or n = ((33/16)^(1/2)+17/4)/2

n in { ((33/16)^(1/2)-17/4)/(-2), ((33/16)^(1/2)+17/4)/2} 

n in { ((33/16)^(1/2)-17/4)/(-2), ((33/16)^(1/2)+17/4)/2 }

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