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2/8x+1/2x=44
We move all terms to the left:
2/8x+1/2x-(44)=0
Domain of the equation: 8x!=0
x!=0/8
x!=0
x∈R
Domain of the equation: 2x!=0We calculate fractions
x!=0/2
x!=0
x∈R
4x/16x^2+8x/16x^2-44=0
We multiply all the terms by the denominator
4x+8x-44*16x^2=0
We add all the numbers together, and all the variables
12x-44*16x^2=0
Wy multiply elements
-704x^2+12x=0
a = -704; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-704)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-704}=\frac{-24}{-1408} =3/176 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-704}=\frac{0}{-1408} =0 $
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