2/9(2m-16)=-1/3(2m+4)

Solution for 2/9(2m-16)=-1/3(2m+4) equation:

2/9(2m-16)=-1/3(2m+4)

We move all terms to the left:

2/9(2m-16)-(-1/3(2m+4))=0


Domain of the equation: 9(2m-16)!=0

m∈R



Domain of the equation: 3(2m+4))!=0

m∈R


We calculate fractions


(6m2/(9(2m-16)*3(2m+4)))+(-(-9m2)/(9(2m-16)*3(2m+4)))=0


We calculate terms in parentheses: +(6m2/(9(2m-16)*3(2m+4))), so:

6m2/(9(2m-16)*3(2m+4))

We multiply all the terms by the denominator


6m2

We add all the numbers together, and all the variables

6m^2

Back to the equation:

+(6m^2)



We calculate terms in parentheses: +(-(-9m2)/(9(2m-16)*3(2m+4))), so:

-(-9m2)/(9(2m-16)*3(2m+4))

We add all the numbers together, and all the variables

-(-9m^2)/(9(2m-16)*3(2m+4))

We multiply all the terms by the denominator


-(-9m^2)

We get rid of parentheses

9m^2

Back to the equation:

+(9m^2)


We add all the numbers together, and all the variables

15m^2=0

a = 15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·15·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{30}=0$