2/9(3-b)=1/3(b-7)

Solution for 2/9(3-b)=1/3(b-7) equation:

2/9(3-b)=1/3(b-7)

We move all terms to the left:

2/9(3-b)-(1/3(b-7))=0


Domain of the equation: 9(3-b)!=0

b∈R



Domain of the equation: 3(b-7))!=0

b∈R


We add all the numbers together, and all the variables

2/9(-1b+3)-(1/3(b-7))=0

We calculate fractions


(6bb/(9(-1b+3)*3(b-7)))+(-9b0/(9(-1b+3)*3(b-7)))=0


We calculate terms in parentheses: +(6bb/(9(-1b+3)*3(b-7))), so:

6bb/(9(-1b+3)*3(b-7))

We multiply all the terms by the denominator


6bb

Back to the equation:

+(6bb)



We calculate terms in parentheses: +(-9b0/(9(-1b+3)*3(b-7))), so:

-9b0/(9(-1b+3)*3(b-7))

We multiply all the terms by the denominator


-9b0

We add all the numbers together, and all the variables

-9b

Back to the equation:

+(-9b)


We get rid of parentheses

6bb-9b=0

We add all the numbers together, and all the variables

-9b+6bb=0