If it's not what You are looking for type in the equation solver your own equation and let us solve it.
Oblicz to!
(2*(2/9))/7 = 0
((2/9)*x^2)/7 = 0
1*x^3-(6*x^2)+11*x-6 = 0
5;6;2;15
{root[2][2-1]}
| 2/9x2/7 | | 3ln(x)+7=0 | | B=6+3x | | 18+(x*0.7)=60 | | x/7-6=! | | 18+0.7x=60 | | 522= | | y=x^4/2-x^2-8 | | 0401634223= | | x^4-x^2+1=x^3 | | 3i^2-x=0 | | x^2+2x-9=x | | 0.2=0.4-y | | 12k/3 | | 2x^2+28x=1156 | | x^2=9x+112 | | 10(4x+1)=8 | | 4x-3-5=8+2x | | mx^2+(2m^2-1)x-2m=0 | | 6*lnx-7=18.2 | | 5(w-8)=2(w+4) | | 8x+17=-25+8x | | 4(2x-3)+1(6x-1)= | | 4(2x-3)+(6x-1)= | | 5cosx+4=0 | | 6-50q=5+8q | | X-5/4-1/2 | | 4x+30=14 | | w(2w+3)=200 | | alog(x)=ln(x) | | 2x^3+9x^2+12x+3=0 | | (x^5)/(x^3) |