2/9=(x+3)/49

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Solution for 2/9=(x+3)/49 equation: 



2/9=(x+3)/49

We move all terms to the left:

2/9-((x+3)/49)=0

We calculate fractions


(-((x+3)*9)/()+()/()=0



We calculate terms in parentheses: +(-((x+3)*9)/()+()/(), so:

-((x+3)*9)/()+()/(

We add all the numbers together, and all the variables

-((x+3)*9)/()+1

We multiply all the terms by the denominator


-((x+3)*9)+1*()



We calculate terms in parentheses: -((x+3)*9), so:

(x+3)*9

We multiply parentheses

9x+27

Back to the equation:

-(9x+27)



We add all the numbers together, and all the variables

-(9x+27)

We get rid of parentheses

-9x-27

Back to the equation:

+(-9x-27)



We get rid of parentheses

-9x-27=0

We move all terms containing x to the left, all other terms to the right

-9x=27

x=27/-9

x=-3

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