2/9=a+17/a

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Solution for 2/9=a+17/a equation:


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

2/9 = a+17/a // - a+17/a

2/9-a-(17/a) = 0

2/9-a-17*a^-1 = 0

2/9*a^0-1*a^1-17*a^-1 = 0

(2/9*a^1-1*a^2-17*a^0)/(a^1) = 0 // * a^2

a^1*(2/9*a^1-1*a^2-17*a^0) = 0

a^1

(2/9)*a-a^2-17 = 0

(2/9)*a-a^2-17 = 0

DELTA = (2/9)^2-(-17*(-1)*4)

DELTA = -5504/81

DELTA < 0

a in { }

a belongs to the empty set

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