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2/9n+2/2=2/3(n+3)
We move all terms to the left:
2/9n+2/2-(2/3(n+3))=0
Domain of the equation: 9n!=0
n!=0/9
n!=0
n∈R
Domain of the equation: 3(n+3))!=0We add all the numbers together, and all the variables
n∈R
2/9n-(2/3(n+3))+1=0
We calculate fractions
(6nn/(27n^2n+(-(2*9n)/(27n^2n+1=0
We can not solve this equation
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