2/9p+7=1/4p

Solution for 2/9p+7=1/4p equation:

2/9p+7=1/4p

We move all terms to the left:

2/9p+7-(1/4p)=0


Domain of the equation: 9p!=0

p!=0/9

p!=0

p∈R



Domain of the equation: 4p)!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

2/9p-(+1/4p)+7=0

We get rid of parentheses

2/9p-1/4p+7=0

We calculate fractions


8p/36p^2+(-9p)/36p^2+7=0

We multiply all the terms by the denominator


8p+(-9p)+7*36p^2=0

Wy multiply elements

252p^2+8p+(-9p)=0

We get rid of parentheses

252p^2+8p-9p=0

We add all the numbers together, and all the variables

252p^2-1p=0

a = 252; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·252·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*252}=\frac{0}{504}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*252}=\frac{2}{504}
=1/252
$