2/n=3/(n-4)

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Solution for 2/n=3/(n-4) equation:


D( n )

n-4 = 0

n = 0

n-4 = 0

n-4 = 0

n-4 = 0 // + 4

n = 4

n = 0

n = 0

n in (-oo:0) U (0:4) U (4:+oo)

2/n = 3/(n-4) // - 3/(n-4)

2/n-(3/(n-4)) = 0

2/n-3*(n-4)^-1 = 0

2/n-3/(n-4) = 0

(-3*n)/(n*(n-4))+(2*(n-4))/(n*(n-4)) = 0

2*(n-4)-3*n = 0

-n-8 = 0

(-n-8)/(n*(n-4)) = 0

(-n-8)/(n*(n-4)) = 0 // * n*(n-4)

-n-8 = 0

-n-8 = 0 // + 8

-n = 8 // * -1

n = -8

n = -8

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