2/n=4+(n+3)

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Solution for 2/n=4+(n+3) equation: 



2/n=4+(n+3)

We move all terms to the left:

2/n-(4+(n+3))=0



Domain of the equation: n!=0

n∈R



We multiply all the terms by the denominator


-((4+(n+3)))*n+2=0

We move all terms containing n to the left, all other terms to the right

-((4+(n+3)))*n=-2

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