2/p+3=7/28p

Solution for 2/p+3=7/28p equation:

2/p+3=7/28p

We move all terms to the left:

2/p+3-(7/28p)=0


Domain of the equation: p!=0

p∈R



Domain of the equation: 28p)!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

2/p-(+7/28p)+3=0

We get rid of parentheses

2/p-7/28p+3=0

We calculate fractions


56p/28p^2+(-7p)/28p^2+3=0

We multiply all the terms by the denominator


56p+(-7p)+3*28p^2=0

Wy multiply elements

84p^2+56p+(-7p)=0

We get rid of parentheses

84p^2+56p-7p=0

We add all the numbers together, and all the variables

84p^2+49p=0

a = 84; b = 49; c = 0;
Δ = b2-4ac
Δ = 492-4·84·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-49}{2*84}=\frac{-98}{168}
=-7/12
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+49}{2*84}=\frac{0}{168}
=0
$