2/t=1/(5t-12)

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Solution for 2/t=1/(5t-12) equation: 


D( t )

5*t-12 = 0

t = 0

5*t-12 = 0

5*t-12 = 0

5*t-12 = 0 // + 12

5*t = 12 // : 5

t = 12/5

t = 0

t = 0

t in (-oo:0) U (0:12/5) U (12/5:+oo)

2/t = 1/(5*t-12) // - 1/(5*t-12)

2/t-(1/(5*t-12)) = 0

2/t-(5*t-12)^-1 = 0

2/t-1/(5*t-12) = 0

(-1*t)/(t*(5*t-12))+(2*(5*t-12))/(t*(5*t-12)) = 0

2*(5*t-12)-1*t = 0

9*t-24 = 0

(9*t-24)/(t*(5*t-12)) = 0

(9*t-24)/(t*(5*t-12)) = 0 // * t*(5*t-12)

9*t-24 = 0

9*t-24 = 0 // + 24

9*t = 24 // : 9

t = 24/9

t = 8/3

t = 8/3

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