2/t=t/(5t-12)

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Solution for 2/t=t/(5t-12) equation:


D( t )

5*t-12 = 0

t = 0

5*t-12 = 0

5*t-12 = 0

5*t-12 = 0 // + 12

5*t = 12 // : 5

t = 12/5

t = 0

t = 0

t in (-oo:0) U (0:12/5) U (12/5:+oo)

2/t = t/(5*t-12) // - t/(5*t-12)

2/t-(t/(5*t-12)) = 0

(-1*t)/(5*t-12)+2/t = 0

(-1*t^2)/(t*(5*t-12))+(2*(5*t-12))/(t*(5*t-12)) = 0

2*(5*t-12)-1*t^2 = 0

10*t-t^2-24 = 0

10*t-t^2-24 = 0

10*t-t^2-24 = 0

DELTA = 10^2-(-24*(-1)*4)

DELTA = 4

DELTA > 0

t = (4^(1/2)-10)/(-1*2) or t = (-4^(1/2)-10)/(-1*2)

t = 4 or t = 6

(t-4)*(t-6) = 0

((t-4)*(t-6))/(t*(5*t-12)) = 0

((t-4)*(t-6))/(t*(5*t-12)) = 0 // * t*(5*t-12)

(t-4)*(t-6) = 0

( t-4 )

t-4 = 0 // + 4

t = 4

( t-6 )

t-6 = 0 // + 6

t = 6

t in { 4, 6 }

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