2/x+10/3x=1

Solution for 2/x+10/3x=1 equation:

2/x+10/3x=1

We move all terms to the left:

2/x+10/3x-(1)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We calculate fractions


6x/3x^2+10x/3x^2-1=0

We multiply all the terms by the denominator


6x+10x-1*3x^2=0

We add all the numbers together, and all the variables

16x-1*3x^2=0

Wy multiply elements

-3x^2+16x=0

a = -3; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·(-3)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*-3}=\frac{-32}{-6}
=5+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*-3}=\frac{0}{-6}
=0
$