2/x+17/5x=27/20

Solution for 2/x+17/5x=27/20 equation:

2/x+17/5x=27/20

We move all terms to the left:

2/x+17/5x-(27/20)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We add all the numbers together, and all the variables

2/x+17/5x-(+27/20)=0

We get rid of parentheses

2/x+17/5x-27/20=0

We calculate fractions


(-675x^2)/200x^2+400x/200x^2+680x/200x^2=0

We multiply all the terms by the denominator


(-675x^2)+400x+680x=0

We add all the numbers together, and all the variables

(-675x^2)+1080x=0

We get rid of parentheses

-675x^2+1080x=0

a = -675; b = 1080; c = 0;
Δ = b2-4ac
Δ = 10802-4·(-675)·0
Δ = 1166400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1166400}=1080$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1080)-1080}{2*-675}=\frac{-2160}{-1350}
=1+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1080)+1080}{2*-675}=\frac{0}{-1350}
=0
$