2/x+1=3/2x+3

Solution for 2/x+1=3/2x+3 equation:

2/x+1=3/2x+3

We move all terms to the left:

2/x+1-(3/2x+3)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 2x+3)!=0

x∈R


We get rid of parentheses

2/x-3/2x-3+1=0

We calculate fractions


4x/2x^2+(-3x)/2x^2-3+1=0

We add all the numbers together, and all the variables

4x/2x^2+(-3x)/2x^2-2=0

We multiply all the terms by the denominator


4x+(-3x)-2*2x^2=0

Wy multiply elements

-4x^2+4x+(-3x)=0

We get rid of parentheses

-4x^2+4x-3x=0

We add all the numbers together, and all the variables

-4x^2+x=0

a = -4; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-4)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-4}=\frac{-2}{-8}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-4}=\frac{0}{-8}
=0
$