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2/x+2+8/3x+6=-9
We move all terms to the left:
2/x+2+8/3x+6-(-9)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
2/x+8/3x+17=0
We calculate fractions
6x/3x^2+8x/3x^2+17=0
We multiply all the terms by the denominator
6x+8x+17*3x^2=0
We add all the numbers together, and all the variables
14x+17*3x^2=0
Wy multiply elements
51x^2+14x=0
a = 51; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·51·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*51}=\frac{-28}{102} =-14/51 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*51}=\frac{0}{102} =0 $
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