2/x+2-1/x-5=-10/2x-4

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Solution for 2/x+2-1/x-5=-10/2x-4 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2/x-(1/x)-5+2 = (-10/2)*x-4 // - (-10/2)*x-4

2/x-((-10/2)*x)-(1/x)-5+2+4 = 0

5*x+2/x-x^-1-5+2+4 = 0

5*x^1+1*x^-1+1*x^0 = 0

(5*x^2+1*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(5*x^2+1*x^1+1*x^0) = 0

x^1

5*x^2+x+1 = 0

5*x^2+x+1 = 0

DELTA = 1^2-(1*4*5)

DELTA = -19

DELTA < 0

x in { }

x belongs to the empty set

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