2/x+2/7x=2

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Solution for 2/x+2/7x=2 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(2/7)*x+2/x = 2 // - 2

(2/7)*x+2/x-2 = 0

2/7*x^1+2*x^-1-2*x^0 = 0

(2/7*x^2-2*x^1+2*x^0)/(x^1) = 0 // * x^2

x^1*(2/7*x^2-2*x^1+2*x^0) = 0

x^1

(2/7)*x^2-2*x+2 = 0

(2/7)*x^2-2*x+2 = 0

DELTA = (-2)^2-(2*4*(2/7))

DELTA = 12/7

DELTA > 0

x = ((12/7)^(1/2)+2)/(2*(2/7)) or x = (2-(12/7)^(1/2))/(2*(2/7))

x = 7/4*((12/7)^(1/2)+2) or x = 7/4*(2-(12/7)^(1/2))

x in { 7/4*(2-(12/7)^(1/2)), 7/4*((12/7)^(1/2)+2)}

x in { 7/4*(2-(12/7)^(1/2)), 7/4*((12/7)^(1/2)+2) }

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