2/x+20-4/x-20=3x/x*2-400

Solution for 2/x+20-4/x-20=3x/x*2-400 equation:

2/x+20-4/x-20=3x/x*2-400

We move all terms to the left:

2/x+20-4/x-20-(3x/x*2-400)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: x*2-400)!=0

x∈R


We add all the numbers together, and all the variables

2/x-4/x-(3x/x*2-400)=0

We get rid of parentheses

2/x-4/x-3x/x*2+400=0

We calculate fractions


(-3x^2)/4x^2+(-16x+2)/4x^2+400=0

We multiply all the terms by the denominator


(-3x^2)+(-16x+2)+400*4x^2=0

Wy multiply elements

(-3x^2)+1600x^2+(-16x+2)=0

We get rid of parentheses

-3x^2+1600x^2-16x+2=0

We add all the numbers together, and all the variables

1597x^2-16x+2=0

a = 1597; b = -16; c = +2;
Δ = b2-4ac
Δ = -162-4·1597·2
Δ = -12520
Delta is less than zero, so there is no solution for the equation