2/x+3+3/8=5/4x+12

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Solution for 2/x+3+3/8=5/4x+12 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2/x+3/8+3 = (5/4)*x+12 // - (5/4)*x+12

2/x-((5/4)*x)+3/8-12+3 = 0

(-5/4)*x+2/x+3/8-12+3 = 0

2*x^-1-5/4*x^1-69/8*x^0 = 0

(2*x^0-5/4*x^2-69/8*x^1)/(x^1) = 0 // * x^2

x^1*(2*x^0-5/4*x^2-69/8*x^1) = 0

x^1

(-5/4)*x^2+(-69/8)*x+2 = 0

(-5/4)*x^2+(-69/8)*x+2 = 0

DELTA = (-69/8)^2-(2*4*(-5/4))

DELTA = 5401/64

DELTA > 0

x = ((5401/64)^(1/2)-(-69/8))/(2*(-5/4)) or x = (-(-69/8)-(5401/64)^(1/2))/(2*(-5/4))

x = -2/5*((5401/64)^(1/2)+69/8) or x = -2/5*(69/8-(5401/64)^(1/2))

x in { -2/5*((5401/64)^(1/2)+69/8), -2/5*(69/8-(5401/64)^(1/2))}

x in { -2/5*((5401/64)^(1/2)+69/8), -2/5*(69/8-(5401/64)^(1/2)) }

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