2/x+3+5/x-2=25/(x+3)(x-2)

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Solution for 2/x+3+5/x-2=25/(x+3)(x-2) equation: 



2/x+3+5/x-2=25/(x+3)(x-2)

We move all terms to the left:

2/x+3+5/x-2-(25/(x+3)(x-2))=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x+3)(x-2))!=0

x∈R



We add all the numbers together, and all the variables

2/x+5/x-(25/(x+3)(x-2))+1=0

We multiply parentheses ..

-(25/(+x^2-2x+3x-6))+2/x+5/x+1=0

We calculate fractions

We do not support expression: x^3

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