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2/x+3/2x=5/6
We move all terms to the left:
2/x+3/2x-(5/6)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
2/x+3/2x-(+5/6)=0
We get rid of parentheses
2/x+3/2x-5/6=0
We calculate fractions
(-20x^2)/72x^2+144x/72x^2+108x/72x^2=0
We multiply all the terms by the denominator
(-20x^2)+144x+108x=0
We add all the numbers together, and all the variables
(-20x^2)+252x=0
We get rid of parentheses
-20x^2+252x=0
a = -20; b = 252; c = 0;
Δ = b2-4ac
Δ = 2522-4·(-20)·0
Δ = 63504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{63504}=252$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(252)-252}{2*-20}=\frac{-504}{-40} =12+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(252)+252}{2*-20}=\frac{0}{-40} =0 $
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