2/x+3=10/8-5x

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Solution for 2/x+3=10/8-5x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2/x+3 = 10/8-(5*x) // - 10/8-(5*x)

5*x+2/x-(10/8)+3 = 0

5*x+2/x-5/4+3 = 0

5*x^1+2*x^-1+7/4*x^0 = 0

(5*x^2+7/4*x^1+2*x^0)/(x^1) = 0 // * x^2

x^1*(5*x^2+7/4*x^1+2*x^0) = 0

x^1

5*x^2+(7/4)*x+2 = 0

5*x^2+(7/4)*x+2 = 0

DELTA = (7/4)^2-(2*4*5)

DELTA = -591/16

DELTA < 0

x in { } 

x belongs to the empty set

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