2/x+3=4/2x+7

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Solution for 2/x+3=4/2x+7 equation: 



2/x+3=4/2x+7

We move all terms to the left:

2/x+3-(4/2x+7)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: 2x+7)!=0

x∈R



We get rid of parentheses

2/x-4/2x-7+3=0

We calculate fractions


4x/2x^2+(-4x)/2x^2-7+3=0

We add all the numbers together, and all the variables

4x/2x^2+(-4x)/2x^2-4=0

We multiply all the terms by the denominator


4x+(-4x)-4*2x^2=0

Wy multiply elements

-8x^2+4x+(-4x)=0

We get rid of parentheses

-8x^2+4x-4x=0

We add all the numbers together, and all the variables

-8x^2=0

a = -8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-8)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-16}=0$

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