2/x+4/x2=7

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Solution for 2/x+4/x2=7 equation:


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

2/x+4/(x^2) = 7 // - 7

2/x+4/(x^2)-7 = 0

2*x^-1+4*x^-2-7 = 0

t_1 = x^-1

4*t_1^2+2*t_1^1-7 = 0

4*t_1^2+2*t_1-7 = 0

DELTA = 2^2-(-7*4*4)

DELTA = 116

DELTA > 0

t_1 = (116^(1/2)-2)/(2*4) or t_1 = (-116^(1/2)-2)/(2*4)

t_1 = (2*29^(1/2)-2)/8 or t_1 = (-2*29^(1/2)-2)/8

t_1 = (-2*29^(1/2)-2)/8

x^-1-((-2*29^(1/2)-2)/8) = 0

1*x^-1 = (-2*29^(1/2)-2)/8 // : 1

x^-1 = (-2*29^(1/2)-2)/8

-1 < 0

1/(x^1) = (-2*29^(1/2)-2)/8 // * x^1

1 = ((-2*29^(1/2)-2)/8)*x^1 // : (-2*29^(1/2)-2)/8

8*(-2*29^(1/2)-2)^-1 = x^1

x = 8*(-2*29^(1/2)-2)^-1

t_1 = (2*29^(1/2)-2)/8

x^-1-((2*29^(1/2)-2)/8) = 0

1*x^-1 = (2*29^(1/2)-2)/8 // : 1

x^-1 = (2*29^(1/2)-2)/8

-1 < 0

1/(x^1) = (2*29^(1/2)-2)/8 // * x^1

1 = ((2*29^(1/2)-2)/8)*x^1 // : (2*29^(1/2)-2)/8

8*(2*29^(1/2)-2)^-1 = x^1

x = 8*(2*29^(1/2)-2)^-1

x in { 8*(-2*29^(1/2)-2)^-1, 8*(2*29^(1/2)-2)^-1 }

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