2/x+4=5/3x+25/6

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Solution for 2/x+4=5/3x+25/6 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2/x+4 = (5/3)*x+25/6 // - (5/3)*x+25/6

2/x-((5/3)*x)-(25/6)+4 = 0

(-5/3)*x+2/x-25/6+4 = 0

2*x^-1-5/3*x^1-1/6*x^0 = 0

(2*x^0-5/3*x^2-1/6*x^1)/(x^1) = 0 // * x^2

x^1*(2*x^0-5/3*x^2-1/6*x^1) = 0

x^1

(-5/3)*x^2+(-1/6)*x+2 = 0

(-5/3)*x^2+(-1/6)*x+2 = 0

DELTA = (-1/6)^2-(2*4*(-5/3))

DELTA = 481/36

DELTA > 0

x = ((481/36)^(1/2)-(-1/6))/(2*(-5/3)) or x = (-(-1/6)-(481/36)^(1/2))/(2*(-5/3))

x = -3/10*((481/36)^(1/2)+1/6) or x = -3/10*(1/6-(481/36)^(1/2))

x in { -3/10*((481/36)^(1/2)+1/6), -3/10*(1/6-(481/36)^(1/2))}

x in { -3/10*((481/36)^(1/2)+1/6), -3/10*(1/6-(481/36)^(1/2)) }

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