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2/x+4=6/2x-1
We move all terms to the left:
2/x+4-(6/2x-1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x-1)!=0We get rid of parentheses
x∈R
2/x-6/2x+1+4=0
We calculate fractions
4x/2x^2+(-6x)/2x^2+1+4=0
We add all the numbers together, and all the variables
4x/2x^2+(-6x)/2x^2+5=0
We multiply all the terms by the denominator
4x+(-6x)+5*2x^2=0
Wy multiply elements
10x^2+4x+(-6x)=0
We get rid of parentheses
10x^2+4x-6x=0
We add all the numbers together, and all the variables
10x^2-2x=0
a = 10; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·10·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*10}=\frac{0}{20} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*10}=\frac{4}{20} =1/5 $
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