2/x+4=6/4x+2

Solution for 2/x+4=6/4x+2 equation:

2/x+4=6/4x+2

We move all terms to the left:

2/x+4-(6/4x+2)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 4x+2)!=0

x∈R


We get rid of parentheses

2/x-6/4x-2+4=0

We calculate fractions


8x/4x^2+(-6x)/4x^2-2+4=0

We add all the numbers together, and all the variables

8x/4x^2+(-6x)/4x^2+2=0

We multiply all the terms by the denominator


8x+(-6x)+2*4x^2=0

Wy multiply elements

8x^2+8x+(-6x)=0

We get rid of parentheses

8x^2+8x-6x=0

We add all the numbers together, and all the variables

8x^2+2x=0

a = 8; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·8·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*8}=\frac{-4}{16}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*8}=\frac{0}{16}
=0
$