2/x+5+4/x-5=40/(x+5)(x-5)

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Solution for 2/x+5+4/x-5=40/(x+5)(x-5) equation: 



2/x+5+4/x-5=40/(x+5)(x-5)

We move all terms to the left:

2/x+5+4/x-5-(40/(x+5)(x-5))=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x+5)(x-5))!=0

x∈R



We add all the numbers together, and all the variables

2/x+4/x-(40/(x+5)(x-5))=0

We use the square of the difference formula

x^2+2/x+4/x+25=0

We multiply all the terms by the denominator


x^2*x+25*x+2+4=0

We add all the numbers together, and all the variables

x^2*x+25x+6=0

Wy multiply elements

x^3+25x+6=0

We do not support expression: x^3

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