2/x+5/2=4-2/3x

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Solution for 2/x+5/2=4-2/3x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2/x+5/2 = 4-((2/3)*x) // - 4-((2/3)*x)

(2/3)*x+2/x+5/2-4 = 0

2/3*x^1+2*x^-1-3/2*x^0 = 0

(2/3*x^2-3/2*x^1+2*x^0)/(x^1) = 0 // * x^2

x^1*(2/3*x^2-3/2*x^1+2*x^0) = 0

x^1

(2/3)*x^2+(-3/2)*x+2 = 0

(2/3)*x^2+(-3/2)*x+2 = 0

DELTA = (-3/2)^2-(2*4*(2/3))

DELTA = -37/12

DELTA < 0

x in { } 

x belongs to the empty set

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