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2/x-10/7x=4
We move all terms to the left:
2/x-10/7x-(4)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 7x!=0We calculate fractions
x!=0/7
x!=0
x∈R
14x/7x^2+(-10x)/7x^2-4=0
We multiply all the terms by the denominator
14x+(-10x)-4*7x^2=0
Wy multiply elements
-28x^2+14x+(-10x)=0
We get rid of parentheses
-28x^2+14x-10x=0
We add all the numbers together, and all the variables
-28x^2+4x=0
a = -28; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-28)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-28}=\frac{-8}{-56} =1/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-28}=\frac{0}{-56} =0 $
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