2/x-2=x/(x-2)-2

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Solution for 2/x-2=x/(x-2)-2 equation:


D( x )

x-2 = 0

x = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x = 0

x = 0

x in (-oo:0) U (0:2) U (2:+oo)

2/x-2 = x/(x-2)-2 // - x/(x-2)-2

2/x-(x/(x-2))-2+2 = 0

(-1*x)/(x-2)+2/x-2+2 = 0

(-1*x^2)/(x*(x-2))+(2*(x-2))/(x*(x-2))+(-2*x*(x-2))/(x*(x-2))+(2*x*(x-2))/(x*(x-2)) = 0

2*(x-2)-2*x*(x-2)+2*x*(x-2)-1*x^2 = 0

2*x^2-x^2-2*x^2+2*x+4*x-4*x-4 = 0

2*x^2-3*x^2+6*x-4*x-4 = 0

2*x-x^2-4 = 0

2*x-x^2-4 = 0

2*x-x^2-4 = 0

DELTA = 2^2-(-4*(-1)*4)

DELTA = -12

DELTA < 0

1 = 0

1/(x*(x-2)) = 0

1/(x*(x-2)) = 0 // * x*(x-2)

1 = 0

x belongs to the empty set

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