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2/x-5+4/3x-15=15
We move all terms to the left:
2/x-5+4/3x-15-(15)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
2/x+4/3x-35=0
We calculate fractions
6x/3x^2+4x/3x^2-35=0
We multiply all the terms by the denominator
6x+4x-35*3x^2=0
We add all the numbers together, and all the variables
10x-35*3x^2=0
Wy multiply elements
-105x^2+10x=0
a = -105; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-105)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-105}=\frac{-20}{-210} =2/21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-105}=\frac{0}{-210} =0 $
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