2/x=3-(7x)/(x-2)

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Solution for 2/x=3-(7x)/(x-2) equation: 



2/x=3-(7x)/(x-2)

We move all terms to the left:

2/x-(3-(7x)/(x-2))=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x-2))!=0

x∈R



We calculate fractions


2x/(-1x^2)+(-(3-7x*x)/(-1x^2)=0



We calculate terms in parentheses: +(-(3-7x*x)/(-1x^2), so:

-(3-7x*x)/(-1x^2

We add all the numbers together, and all the variables

-(-7x*x+3)/(-1x^2

We multiply all the terms by the denominator


-(-7x*x+3)

We get rid of parentheses

7x*x-3

Wy multiply elements

7x^2-3

Back to the equation:

+(7x^2-3)



We get rid of parentheses

2x/(-1x^2)+7x^2-3=0

We multiply all the terms by the denominator


7x^2*(-1x^2)-3*(-1x^2)+2x=0

We multiply parentheses

7x^2*(-1x^2)+3x^2+2x=0

We add all the numbers together, and all the variables

3x^2+7x^2*(-1x^2)+2x=0

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