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2/x=4/9x+4
We move all terms to the left:
2/x-(4/9x+4)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 9x+4)!=0We get rid of parentheses
x∈R
2/x-4/9x-4=0
We calculate fractions
18x/9x^2+(-4x)/9x^2-4=0
We multiply all the terms by the denominator
18x+(-4x)-4*9x^2=0
Wy multiply elements
-36x^2+18x+(-4x)=0
We get rid of parentheses
-36x^2+18x-4x=0
We add all the numbers together, and all the variables
-36x^2+14x=0
a = -36; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·(-36)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*-36}=\frac{-28}{-72} =7/18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*-36}=\frac{0}{-72} =0 $
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