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2/x=5/(x+1
We move all terms to the left:
2/x-(5/(x+1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x+1)!=0We calculate fractions
We move all terms containing x to the left, all other terms to the right
x!=-1
x∈R
(2x+2)/(x^2+x)+(-(5*x)/(x^2+x)=0
We calculate terms in parentheses: +(-(5*x)/(x^2+x), so:We get rid of parentheses
-(5*x)/(x^2+x
We add all the numbers together, and all the variables
-(+5x)/(x^2+x
We multiply all the terms by the denominator
-(+5x)
We get rid of parentheses
-5x
Back to the equation:
+(-5x)
(2x+2)/(x^2+x)-5x=0
We multiply all the terms by the denominator
(2x+2)-5x*(x^2+x)=0
We multiply parentheses
-5x^3-5x^2+(2x+2)=0
We get rid of parentheses
-5x^3-5x^2+2x+2=0
We do not support expression: x^3
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