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2/x=8/5x+2
We move all terms to the left:
2/x-(8/5x+2)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 5x+2)!=0We get rid of parentheses
x∈R
2/x-8/5x-2=0
We calculate fractions
10x/5x^2+(-8x)/5x^2-2=0
We multiply all the terms by the denominator
10x+(-8x)-2*5x^2=0
Wy multiply elements
-10x^2+10x+(-8x)=0
We get rid of parentheses
-10x^2+10x-8x=0
We add all the numbers together, and all the variables
-10x^2+2x=0
a = -10; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-10)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-10}=\frac{-4}{-20} =1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-10}=\frac{0}{-20} =0 $
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